## Basic College Mathematics (9th Edition)

Area of the Triangle = $A$ = 28.125 ft$^{2}$ Perimeter of the Triangle = $P$ = 37 ft
Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(9 ft)(6.25 ft) $A$ = 28.125 ft$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 18 ft + 9 ft + 10 ft $P$ = 37 ft