## Basic College Mathematics (9th Edition)

The area of the triangle is $128$ in$^{2}$ and the perimeter of the triangle is $54.6$ in.
1. Find the area of the triangle Let $A =$ area of the triangle $A = base \times height \div 2$ $A = (16 \times 16)\div2$ $A = 128$ in$^{2}$ 2. Find the perimeter of the triangle Let $P =$ the perimeter of the triangle $P = a + b + c$ $P = 16 + 16 + 22.6$ $P = 54.6$ in.