## Basic College Mathematics (9th Edition)

Published by Pearson

# Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 9

#### Answer

$A$ = 1674.2 ft$^{2}$ $P$ = 196.2 ft

#### Work Step by Step

Since the length and width of the object are different it is a rectangle. Area of a rectangle: $A$ = $l$ * $w$ $A$ = 76.1 ft * 22 ft $A$ = 1674.2 ft$^{2}$ Perimeter of a rectangle: $P$ = 2$l$ + 2$w$ $P$ = 2(76.1 ft) + 2(22 ft) $P$ = 152.2 ft + 44 ft $P$ = 196.2 ft

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