Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 552: 3

Answer

P = 16 yd + 12 yd P = 28 yd A = 48 yd$^{2}$

Work Step by Step

Area = A A = $l$*$w$ A = 8yd * 6yd A = 48 yd$^{2}$ Perimeter = P P = 2$l$ + 2$w$ P = 2(8 yd) + 2(6 yd) P = 16 yd + 12 yd P = 28 yd
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