## Basic College Mathematics (9th Edition)

$1\frac{3}{4}$
$4(\frac{7}{8}-\frac{7}{16})$ = $4(\frac{7\times2}{8\times2}-\frac{7}{16})$ (First Solve Bracket) = $4(\frac{14}{16}-\frac{7}{16})$ = $4(\frac{14-7}{16})$ = $4(\frac{7}{16})$ = $4\times\frac{7}{16}$ = $\frac{7}{4}$ = $1\frac{3}{4}$