Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Test - Page 260: 25

Answer

$1\frac{1}{3}$

Work Step by Step

$\frac{5}{6}+\frac{4}{3}.(\frac{3}{8})$ = $\frac{5}{6}+\frac{4}{3}\times\frac{3}{8}$ (First Solve Bracket) = $\frac{5}{6}+\frac{1}{2}$ = $\frac{5}{6}+\frac{1\times3}{2\times3}$ (Least common multiple of 6 & 2 is 6) = $\frac{5}{6}+\frac{3}{6}$ = $\frac{5+3}{6}$ = $\frac{8}{6}$ = $\frac{4}{3}$ = $1\frac{1}{3}$
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