Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-3 - Adding and Subtracting Fractions - Cumulative Review - Page 262: 23

Answer

$2\frac{3}{16}$

Work Step by Step

$\frac{25}{40}\div\frac{10}{35}$ = $\frac{25}{40}\times\frac{35}{10}$ (division of factors i.e. multiply by the reciprocal of the second factor) = $\frac{5\times5}{2\times2\times2\times5}\times\frac{5\times7}{2\times5}$ (representing as prime factorization) = $\frac{1\times5}{2\times2\times2\times1}\times\frac{1\times7}{2\times1}$ = $\frac{5\times7}{2\times2\times2\times2}$ = $\frac{35}{16}$ = $2\frac{3}{16}$
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