## Basic College Mathematics (10th Edition)

$\frac{9}{10}$
$\frac{3}{4}\div(\frac{1}{3}+\frac{1}{2})$ (First solve Bracket) = $\frac{3}{4}\div(\frac{1\times2}{3\times2}+\frac{1\times3}{2\times3})$ (LCM of 3 & 2 is 6) = $\frac{3}{4}\div(\frac{2}{6}+\frac{3}{6})$ = $\frac{3}{4}\div(\frac{2+3}{6})$ (addition of fractions with same denomiator) = $\frac{3}{4}\div(\frac{5}{6})$ = $\frac{3}{4}\div\frac{5}{6}$ = $\frac{3}{4}\times\frac{6}{5}$ = $\frac{3}{2}\times\frac{3}{5}$ = $\frac{9}{10}$