Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - Test - Page 702: 29

Answer

Length $= 168$ ft Width $= 42$ ft

Work Step by Step

$x =$ width $4x =$ length 1. Find $x$ Let $P =$ perimeter of the rectangle $2(4x) + 2(x) = 420$ $8x + 2x = 420$ $10x = 420$ $x = 42$ 2. Substitute $x$ into the length and width equations a) Width $x = 42$ ft Therefore the width of the rectangular building is $= 42$ ft b) Length $4x = 4(42)$ $4x = 168$ ft Therefore the length of the rectangular building is $= 168$ ft.
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