Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Test - Page 702: 26



Work Step by Step

We are given the equation $-15=3(a-2)$. In order to solve, we can use the distributive property to simplify on the right side. $-15=3(a-2)=3(a)+3(-2)=3a-6$ Add 6 to both sides. $-15+6=3a-6+6$ $-9=3a$ Divide both sides by 3. $\frac{-9}{3}=\frac{3a}{3}$ Therefore, $a=-3$.
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