Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - Review Exercises - Page 695: 20

Answer

$-\frac{3}{8}$

Work Step by Step

$-\frac{7}{8}+\frac{1}{2}=-\frac{7}{8}+\frac{1\times4}{2\times4}=-\frac{7}{8}+\frac{4}{8}=\frac{4}{8}-\frac{7}{8}=\frac{4-7}{8}=-\frac{3}{8}$
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