Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 695: 19

Answer

$\frac{3}{10}$

Work Step by Step

$\frac{9}{10}+(-\frac{3}{5})=\frac{9}{10}+(-\frac{3\times2}{5\times2})=\frac{9}{10}+(-\frac{6}{10})=\frac{9}{10}-\frac{6}{10}=\frac{9-6}{10}=\frac{3}{10}$
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