Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 671: 80



Work Step by Step

We are given the equation $\frac{2}{3}-\frac{8}{9}=\frac{c}{6}$. To solve, we must first combine like terms on the left side. $\frac{2}{3}-\frac{8}{9}=\frac{2\times3}{3\times3}-\frac{8}{9}=\frac{6}{9}-\frac{8}{9}=\frac{6-8}{9}=-\frac{2}{9}=\frac{c}{6}$ Multiply both sides by 6. $-\frac{2}{9}\times6=-\frac{12}{9}=-\frac{4}{3}=(\frac{c}{6}\times6)=c$ $c=-\frac{4}{3}$
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