Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 671: 67



Work Step by Step

We are given the equation $6=\frac{3}{8}x$. Multiply both sides by $\frac{8}{3}$. $6\times\frac{8}{3}=\frac{6\times8}{3}=\frac{48}{3}=16=(\frac{3}{8}x\times\frac{8}{3})=x$ Therefore, $x=16$.
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