Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises - Page 671: 68



Work Step by Step

We are given the equation $4=\frac{2}{3}a$. Multiply both sides by $\frac{3}{2}$. $4\times\frac{3}{2}=\frac{4\times3}{2}=\frac{12}{2}=6=(\frac{2}{3}a\times\frac{3}{2})=a$ Therefore, $a=6$.
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