Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - 9.5 Evaluating Expressions and Formulas - 9.5 Exercises - Page 660: 18

Answer

$3\frac{2}{3}$

Work Step by Step

We have $$7k-3r$$ Where $k = \frac{2}{3}$, $r=\frac{1}{3}$ Then if you substitute each letter by her value $$7*\frac{2}{3} - 3*\frac{1}{3} = \frac{14}{3} - \frac{3}{3} = \frac{14-3}{3} = \frac{11}{3} = 3\frac{2}{3}$$
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