Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.5 Evaluating Expressions and Formulas - 9.5 Exercises - Page 660: 18



Work Step by Step

We have $$7k-3r$$ Where $k = \frac{2}{3}$, $r=\frac{1}{3}$ Then if you substitute each letter by her value $$7*\frac{2}{3} - 3*\frac{1}{3} = \frac{14}{3} - \frac{3}{3} = \frac{14-3}{3} = \frac{11}{3} = 3\frac{2}{3}$$
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