Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - 9.5 Evaluating Expressions and Formulas - 9.5 Exercises - Page 660: 16

Answer

$5$

Work Step by Step

We have $$\frac{2y-z}{x-2}$$ Where $y=0$, $z=5$ and $x=1$ Then if you substitute each letter by her value $$\frac{2(0)-(5)}{1-2}$$ $$\frac{0-5}{-1}$$ $$\frac{-5}{-1}$$ $$5$$
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