Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.4 Order of Operations - 9.4 Exercises - Page 655: 57

Answer

$\frac{4}{5}$

Work Step by Step

$\frac{3}{5}(-\frac{7}{6}) - (\frac{1}{6}-\frac{5}{3}) = -\frac{21}{30} - (\frac{1-10}{6}) = -\frac{7}{10} - (\frac{-9}{6}) = -\frac{7}{10} + \frac{3}{2} = \frac{-7 + 15}{10} = \frac{8}{10} = \frac{4}{5}$
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