Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 9 - Basic Algebra - 9.4 Order of Operations - 9.4 Exercises - Page 655: 68

Answer

$0$

Work Step by Step

$6 - (2-12) + 4^2\div(-2)(\frac{5}{2}) + (2)^2 = 6 - (-10) + 16\div(-2)(\frac{5}{2}) + 4 = 6 + 10 -20 + 4 = 0$
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