## Basic College Mathematics (10th Edition)

The perimeter is $37.8$ yd and the area is $58.5$ sq yd.
1. Find the perimeter of the triangle Let $P =$ the perimeter of the triangle $P = 9 + 13 + 15.8$ $P = 37.8$ yd 2. Find the area of the triangle Let $A =$ the area $A = (9 \times 13) \div 2$ $A = 117 \div 2$ $A = 58.5$ sq yd