## Basic College Mathematics (10th Edition)

The perimeter is $32.45$ meters and the area is $48$ m$^{2}$.
1. Find the perimeter of the triangle by adding the sides up Let $P =$ the perimeter of the triangle $P = 11.8 + 8.65 + 12$ $P = 32.45$ m 2. Find the area of the triangle Let $A =$ the area of the triangle $A =( base \times height) \div 2$ $A = (12 \times 8) \div 2$ $A = 96 \div 2$ $A = 48$ m$^{2}$