## Basic College Mathematics (10th Edition)

$\approx 84.9$ feet
(a) See image below. (b) To find the distance from home plate to second base, we divide the square in two pieces to form a right triangle. We know that for a right triangle the Pythagorean Theorem states: $leg_1^2+leg_2^2=hypotenuse^2$ $a^2+b^2=c^2$ Our legs are 60 ft long, so we have: $60^2+60^2=c^2$ $3600+3600=c^2$ $7200=c^2$ $c=\sqrt{7200}$ $c\approx 84.9$ feet