Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 594: 48

Answer

$\approx 84.9$ feet

Work Step by Step

(a) See image below. (b) To find the distance from home plate to second base, we divide the square in two pieces to form a right triangle. We know that for a right triangle the Pythagorean Theorem states: $leg_1^2+leg_2^2=hypotenuse^2$ $a^2+b^2=c^2$ Our legs are 60 ft long, so we have: $60^2+60^2=c^2$ $3600+3600=c^2$ $7200=c^2$ $c=\sqrt{7200}$ $c\approx 84.9$ feet
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