## Basic College Mathematics (10th Edition)

The distance from his current and initial position is $\approx 16.6$ miles.
1. Find the distance between his current position and his initial position Let $x =$ the distance $a^{2} + b^{2} = x^{2}$ $x = \sqrt(a^{2} + b^{2})$ $x = \sqrt(15^{2} + 7^{2})$ $x = \sqrt (274)$ $x = 16.5529...$ miles $x \approx 16.6$ miles