Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 6 - Percent - Review Exercises - Page 469: 34

Answer

The percent of decrease is 33.4%.

Work Step by Step

The amount of change is $42.8-28.5=14.3$. $\frac{part}{whole}=\frac{percent}{100}$ $\frac{14.3}{42.8}=\frac{p}{100}$ Cross multiply to solve for p. $42.8p=(14.3)(100)$ $42.8p\div42.8=1430\div42.8$ $p=33.4112$
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