## Basic College Mathematics (10th Edition)

Published by Pearson

# Chapter 3 - Adding and Subtracting Fractions - Mixed Review Exercises - Page 258: 15

#### Answer

$\frac{2}{3}\gt\frac{7}{12}$

#### Work Step by Step

$\frac{2}{3}$, $\frac{7}{12}$ to compare two fractions lets have common denominator. 3 & 12 has least common multiple as 12. So multiply $\frac{2}{3}$ with 4 in numerator and denominator. $\frac{2\times4}{3\times4}$ = $\frac{8}{12}$ Now, $\frac{8}{12}\gt\frac{7}{12}$ (numerator of first fraction is greater then second) = $\frac{2}{3}\gt\frac{7}{12}$

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