Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - Mixed Review Exercises - Page 258: 12

Answer

$\frac{1}{2}$

Work Step by Step

$\frac{3}{8}\div(\frac{1}{2}+\frac{1}{4})$ = $\frac{3}{8}\div(\frac{1}{2}+\frac{1}{4})$ (First solve bracket) = $\frac{3}{8}\div(\frac{1\times2}{2\times2}+\frac{1}{4})$ (least common multiple of 2 &4 is 4) = $\frac{3}{8}\div(\frac{2}{4}+\frac{1}{4})$ = $\frac{3}{8}\div(\frac{2+1}{4})$ (add numerators) = $\frac{3}{8}\div(\frac{3}{4})$ = $\frac{3}{8}\times(\frac{4}{3})$ (reciprocal) = $\frac{1}{2}$
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