Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 245: 61

Answer

3

Work Step by Step

$\frac{3}{8}(\frac{1}{4} + \frac{1}{2}) \times\frac{32}{3}$ = $\frac{3}{8}(\frac{1}{4} + \frac{2}{4}) \times\frac{32}{3}$ = $\frac{3}{8}(\frac{3}{4}) \times\frac{32}{3}$ = $\frac{9}{32} \times \frac{32}{3}$ = $\frac{9}{1} \times \frac{1}{3}$ = $\frac{9}{3}$ = 3
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.