Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 245: 57

Answer

$1 \frac{1}{2}$

Work Step by Step

$\frac{9}{8} \div (\frac{2}{3} + \frac{1}{12})$ = $\frac{9}{8} \div (\frac{8}{12} + \frac{1}{12})$ = $\frac{9}{8} \div \frac{9}{12}$ = $\frac{9}{8} \times \frac{12}{9}$ = $\frac{1}{8} \times \frac{12}{1}$ = $\frac{12}{8}$ = $1 \frac{4}{8}$ = $1 \frac{1}{2}$
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