Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 243: 25

Answer

$\frac{1}{9}$

Work Step by Step

$(\frac{1}{3})^{2}=\frac{1}{3}\times\frac{1}{3}=\frac{1\times1}{3\times3}=\frac{1}{9}$
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