Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 3 - Adding and Subtracting Fractions - 3.5 Order Relation and the Order of Operations - 3.5 Exercises - Page 243: 20

Answer

$\frac{7}{12}\gt\frac{11}{20}$

Work Step by Step

We can rewrite $\frac{7}{12}=\frac{7\times5}{12\times5}=\frac{35}{60}$ and $\frac{11}{20}=\frac{11\times3}{20\times3}=\frac{33}{60}$. $\frac{35}{60}$ is greater than $\frac{33}{60}$, because its numerator is greatest while both denominators are the same Therefore, $\frac{7}{12}\gt\frac{11}{20}$.
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