Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 2 - Multiplying and Dividing Fractions - Summary Exercises - Fraction Basics - Page 141: 32



Work Step by Step

In order to find the prime factorization by 360, we can try to divide 360 by the first prime number, 2. $360\div2=180$ Try to divide 180 by 2. $180\div2=90$ Try to divide 90 by 2. $90\div2=45$ 45 is not divisible by 2, so we can divide by the next prime, 3. $45\div3=15$ 15 is not divisible by 2, so we can divide by 3. $15\div3=5$ The number 5 itself is a prime number. Therefore, the prime factorization of 360 is $2\times2\times2\times3\times3\times5=2^{3}\times3^{2}\times5$.
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