Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 2 - Multiplying and Dividing Fractions - Summary Exercises - Fraction Basics - Page 141: 29

Answer

$2^{2}\times3^{2}$

Work Step by Step

In order to find the prime factorization by 36, we can try to divide 36 by the first prime number, 2. $36\div2=18$ Try to divide 18 by 2. $18\div2=9$ 9 is not divisible by 2, so we divide it by the next prime, 3. $9\div3=3$ The number 3 itself is a prime number. Therefore, the prime factorization of 36 is $2\times2\times3\times3=2^{2}\times3^{2}$.
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