## Basic College Mathematics (10th Edition)

Published by Pearson

# Chapter 2 - Multiplying and Dividing Fractions - 2.4 Writing a Fraction in Lowest Terms - 2.4 Exercises - Page 136: 6

#### Answer

Divisible by 2, 3, 5, and 10

#### Work Step by Step

$90\div2=45$ with a remainder of 0 $90\div3=30$ with a remainder of 0 $90\div5=18$ with a remainder of 0 $90\div10=9$ with a remainder of 0 Therefore, 90 is divisible by 2, 3, 5, and 10.

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