Divisible by 2, 3, 5, and 10
Work Step by Step
$90\div2=45$ with a remainder of 0 $90\div3=30$ with a remainder of 0 $90\div5=18$ with a remainder of 0 $90\div10=9$ with a remainder of 0 Therefore, 90 is divisible by 2, 3, 5, and 10.
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