Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapter 2 - Multiplying and Dividing Fractions - 2.4 Writing a Fraction in Lowest Terms - 2.4 Exercises - Page 136: 11


Divisible by 2 and 3

Work Step by Step

$138\div2=69$ with a remainder of 0 $138\div3=46$ with a remainder of 0 $138\div5=27$ with a remainder of 3 $138\div10=13$ with a remainder of 8 Therefore, 138 is divisible by 2 and 3.
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