Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - Chapter Test - Page 537: 2

Answer

$x = 2\sqrt {14}$

Work Step by Step

We can find the third side by using the Pythagorean theorem, which states that $a^2 + b^2 = c^2$, where $a$ and $b$ are the legs of the right triangle and $c$ is the hypotenuse. Let's plug in what we know into the Pythagorean theorem: $x^2 + 13^2 = 15^2$ Evaluate the exponents: $x^2 + 169 = 225$ Subtract $169$ from each side of the equation: $56 = x^2$ Rewrite $56$ as the product of a perfect square and another factor: $x^2 = 4 • 14$ Take the positive square root to solve for $x$: $x = 2\sqrt {14}$
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