## Geometry: Common Core (15th Edition)

$x \approx 41^{\circ}$
In this exercise, we are given the side opposite to $\angle x$ and the side adjacent to $\angle x$. We can use the tangent ratio to find $x$: tan $x = \frac{opposite}{adjacent}$ Let's plug in what we know: tan $x = \frac{6}{7}$ Take $tan^{-1}$ of both sides to find the measure of $x$: $x \approx 41^{\circ}$