Answer
$x = 7$
$y = 7\sqrt 2$
Work Step by Step
In a $45^{\circ}-45^{\circ}-90^{\circ}$ triangle, the hypotenuse is $\sqrt 2$ times each leg. Let's write an equation to solve for $y$, the length of the hypotenuse:
$y = \sqrt 2(7)$
Let's rewrite the radical in a more standard form:
$y = 7\sqrt 2$
For $x$, we know that in this type of triangle, the legs are congruent to one another. Since one leg measures $7$, $x$, the other leg, also equals $7$.
