Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - Chapter Review - Page 535: 6

Answer

$x = 12\sqrt 2$

Work Step by Step

We can find the third side by using the Pythagorean theorem, which states that $a^2 + b^2 = c^2$, where $a$ and $b$ are the legs of the right triangle and $c$ is the hypotenuse. Both legs have lengths of $12$ because they are marked as congruent. Let's plug in what we know into the Pythagorean theorem: $12^2 + 12^2 = x^2$ Evaluate the exponents: $144 + 144 = x^2$ Add to simplify: $288 = x^2$ Rewrite $288$ as the product of a perfect square and another factor: $x^2 = 144 • 2$ Take the positive square root to solve for $x$: $x = 12\sqrt 2$
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