## Geometry: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 8 - Right Triangles and Trigonometry - 8-5 Law of Sines - Lesson Check - Page 524: 3

#### Answer

$x\approx19.1$ $y\approx14.5$

#### Work Step by Step

$\frac{sin(63)}{18}=\frac{sin(71)}{x}$--> set terms into Law of Sines $x(\frac{sin(63)}{18})=sin(71)$--> multiply both sides by term x $x=\frac{sin(71)}{\frac{sin(63)}{18}}$--> divide both sides by term $\frac{sin(63)}{18}$ to isolate x $x\approx19.1$ --> plug into a calculator and round to the nearest tenth $\frac{sin(46)}{y}=\frac{sin(63)}{18}$--> set terms into law of sines $sin(46)=y(\frac{sin(63)}{18})$--> multiply both sides by term y $\frac{sin(46)}{\frac{sin(63)}{18}}=y$ --> divide both sides by $\frac{sin 63}{18}$ to isolate y $y\approx14.5$--> plug into a calculator and round to the nearest tenth

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