Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-5 Law of Sines - Lesson Check - Page 524: 3

Answer

$x\approx19.1$ $y\approx14.5$

Work Step by Step

$\frac{sin(63)}{18}=\frac{sin(71)}{x}$--> set terms into Law of Sines $x(\frac{sin(63)}{18})=sin(71)$--> multiply both sides by term x $x=\frac{sin(71)}{\frac{sin(63)}{18}}$--> divide both sides by term $\frac{sin(63)}{18}$ to isolate x $x\approx19.1$ --> plug into a calculator and round to the nearest tenth $\frac{sin(46)}{y}=\frac{sin(63)}{18}$--> set terms into law of sines $sin(46)=y(\frac{sin(63)}{18})$--> multiply both sides by term y $\frac{sin(46)}{\frac{sin(63)}{18}}=y$ --> divide both sides by $\frac{sin 63}{18}$ to isolate y $y\approx14.5$--> plug into a calculator and round to the nearest tenth
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.