Answer
$x \approx 18.1$
Work Step by Step
In this exercise, we are given the measure of an angle and two sides. We can use the law of sines to find the measure of another angle in the triangle. The law of sines states the following:
$\frac{sin G}{\overline{HK}}$ = $\frac{sin H}{\overline{GK}}$ = $\frac{sin K}{\overline{GH}}$, where $G$, $H$, and $K$ are the measures of the angles in the triangle and $\overline{HK}$, $\overline{GK}$ and $\overline{GH}$ are the measures of the sides opposite those angles, respectively.
Let's plug in what we know into the formula:
$\frac{sin 62}{16}$ = $\frac{sin 88}{x}$
Multiply each side by $x$:
$\frac{sin 62}{16}(x)$ = sin $88$
Divide each side of the equation by $\frac{sin 62}{16}$ to solve for $x$:
$x \approx 18.1$
