## Geometry: Common Core (15th Edition)

$\sqrt {11}$
We can find the other leg by using the Pythagorean theorem, which states that $a^2 + b^2 = c^2$, where $a$ and $b$ are the legs of the right triangle and $c$ is the hypotenuse. Let's plug in what we know into the Pythagorean theorem: $5^2 + b^2 = 6^2$ Evaluate the exponents: $25 + b^2 = 36$ Subtract $25$ from each side of the equation to move constants to the right side of the equation: $b^2 = 11$ Take the positive square root to solve for $b$: $b = \sqrt {11}$ The other leg would be $\sqrt {11}$.