## Geometry: Common Core (15th Edition)

$\frac{16 \sqrt 3}{3}$
$\frac{16}{\sqrt 3}$ We want to get rid of the radical in the denominator, so we multiply both the numerator and denominator by $\sqrt 3$: $\frac{16}{\sqrt 3} • \frac{\sqrt 3}{\sqrt 3}$ Multiply to simplify: $\frac{16 \sqrt 3}{\sqrt 9}$ Take the square root of the denominator: $\frac{16 \sqrt 3}{3}$