Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - 8-1 The Pythagorean Theorem and It's Converse - Practice and Problem-Solving Exercises - Page 498: 60

Answer

$\sqrt 3$

Work Step by Step

$\sqrt 9$/$\sqrt 3$ $\sqrt {9/3}$= $\sqrt 3$ $\sqrt 3$
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