Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-4 Similarity in Right Triangles - Practice and Problem-Solving Exercises - Page 467: 48

Answer

$B$

Work Step by Step

The altitude of a right triangle is the geometric mean of the lengths of the two hypotenuse segments. Let's set up that proportion: $\frac{a}{x} = \frac{x}{b}$, where $a$ and $b$ are the lengths of the two hypotenuse segments and $x$ is the length of the altitude. Let's plug in our numbers: $\frac{5}{x} = \frac{x}{15}$ Use the cross products property to get rid of the fractions: $x^2 = 75$ Rewrite $75$ as the product of a perfect square and another factor: $x^2 = 25 • 3$ Take the positive square root of each factor to solve for $x$: $x = 5 \sqrt {3}$ The answer is $B$.
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