Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-4 Similarity in Right Triangles - Practice and Problem-Solving Exercises - Page 465: 16

Answer

$4 \sqrt 3$

Work Step by Step

The geometric mean of two numbers can be found using the following proportion: $\frac{a}{x} = \frac{x}{b}$, where $a$ and $b$ are positive numbers and $x$ is the geometric mean. Let's plug in our numbers: $\frac{3}{x} = \frac{x}{16}$ Use the cross products property to get rid of the fractions: $x^2 = 48$ Rewrite $48$ as the product of a perfect square and another factor: $x^2 = 16 • 3$ Take the positive square root of each factor to solve for $x$: $x = 4 \sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.