Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 7 - Similarity - 7-4 Similarity in Right Triangles - Practice and Problem-Solving Exercises - Page 465: 15

Answer

$3 \sqrt 7$

Work Step by Step

The geometric mean of two numbers can be found using the following proportion: $\frac{a}{x} = \frac{x}{b}$, where $a$ and $b$ are positive numbers and $x$ is the geometric mean. Let's plug in our numbers: $\frac{7}{x} = \frac{x}{9}$ Use the cross products property to get rid of the fractions: $x^2 = 63$ Rewrite $63$ as the product of a perfect square and another factor: $x^2 = 9 • 7$ Take the positive square root of each factor to solve for $x$: $x = 3 \sqrt 7$
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