Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - Algebra Review - Page 399: 5


$4\sqrt {3}$

Work Step by Step

First, we write both numbers under the same radical: $\sqrt {6} • \sqrt {8} = \sqrt {6 • 8}$ Multiply what is under the radical sign: $\sqrt {48}$ Rewrite $48$ as a product of a perfect square and another factor. We can use $16$ as the perfect square factor: $\sqrt {16 • 3}$ Take the square root of $16$ to simplify: $4\sqrt {3}$
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