Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 6 - Polygons and Quadrilaterals - Algebra Review - Page 399: 2

Answer

$9\sqrt {3}$

Work Step by Step

Rewrite $243$ as a product of a perfect square and another factor. We can use $81$ as the perfect square factor: $\sqrt {81 • 3}$ Take the square root of $81$ to simplify: $9\sqrt {3}$
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