Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 5 - Relationships Within Triangles - 5-3 Bisectors in Triangles - Practice and Problem-Solving Exercises - Page 307: 40


The midpoint of $\overline{AB}$ is $(5, \frac{7}{2})$.

Work Step by Step

The midpoint of $\overline{AB}$ can be found using the following formula: $M = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$ The points we are given are $(6, 8)$ and $(4, -1)$. Let's plug these points into the formula: $M = (\frac{6 + 4}{2}, \frac{8 + (-1)}{2})$ Use addition to simplify: $M = (\frac{10}{2}, \frac{7}{2})$ $M = (5, \frac{7}{2})$ The midpoint of $\overline{AB}$ is $(5, \frac{7}{2})$.
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