Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 4 - Congruent Triangles - Algebra Review - Page 257: 8


The solution is $(6, 11)$.

Work Step by Step

We can use the first equation to substitute for $y$ in the second equation. Then we can solve for $x$ first: $2x - 1 = 3x - 7$ Move the $x$ terms to the left side of the equation by subtracting $3x$ from each side of the equation: $-x - 1 = -7$ Move constants to the right side of the equation by adding $1$ to each side of the equation: $-x = -6$ Divide each side of the equation by $-1$ to solve for $x$: $x = 6$ Now that we have the value of $x$, let's plug this value for $x$ into the first equation: $y = 2(6) - 1$ Multiply first to simplify: $y = 12 - 1$ Subtract to solve: $y = 11$ The solution is $(6, 11)$.
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